Get the file name using XSLT mapping

[Former Member]

Hi

How to get the file Name at receiver side using XSLT mapping.

Could any one please help me

Regards

sowmya

[Former Member]

Hi,

You can use XSLT mapping with Java enhancement. Refer below link and try to use above code in XSLT.

http://help.sap.com/saphelp_nw04/helpdata/en/14/80243b4a66ae0ce10000000a11402f/frameset.htm

Thanks,

RamuV

[Former Member]

Sowmya

If you will use Grpahical Mesage Mapping then this can be achieved using Adapter-Specific Attribute u201CFileNameu201D

http://help.sap.com/saphelp_nw04/helpdata/en/43/03612cdecc6e76e10000000a422035/content.htm

Code Snippet -->

DynamicConfiguration conf = (DynamicConfiguration) container

.getTransformationParameters()

.get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);

DynamicConfigurationKey key = DynamicConfigurationKey.create(

u201Chttp://sap.com/xi/XI/System/Fileu201D,

u201CFileNameu201D);

But in case you have to ONLY use XSLT mapping then I would suggest to use the same jave code & call it from your XSLT mapping. I never tried such thing you might use couple of jar files too.

- lalit -

[santhosh_kumarv]

Hi,

1. Select the option Adapter Specific Attribute in the sender file adapter.

2. Use the Dynamic Configuration to retreive the file name.

DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);

DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");

String SourceFileName = conf.get(key);

Thanks

SaNv...

[Former Member]

Hi

But here i am not using graphical mapping. I am using XSLT mapping . Where to write this code

Regards

sowmya