on 07-25-2008 9:47 AM
Hi Experts...
Can someone help me with the below mapping logic?
if A_NUM = B_NUM; pass NAME
Here is the source structure:
ROOT
NODE1
NODE2
A_NUM
NODE3
B_NUM
NAME
NODE4
B_NUM
NAME
Thanks in advance!
HI,
If a_num(change its context to its parent(node1)) EqualsS B_num then map the name to target....
drag and drop ifwith out else.....and take a equalsS from text functions and do as said above...
thanks,
Mahdu
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Hi Smitha ,
Do this way -
For A_Num define the context at the level of Node1.
For all other nodes which have B_Num as element set the context to root node.
You get data in queue like this - A_num and context change and after that you will have all nodes as values in single context.
Get the value of A_Num = loop at the B_Num and pass the name value to output.
With the above context set you can write a UDF which will map name to right value in target structure.
Regards,
Kishore
Assign Context of A_Num to parent Node NODE1,
if A_NUM = B_NUM; pass NAME
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