on 05-05-2008 5:02 AM
Hi friends...
I am working on RFC to HTTP scenario. I need to send the parameter for URL from RFC and get back the response. Can anyone help me. How to configure the the Receiver HTTP communication channel ?
Refer these blogs
/people/kausik.medavarapu/blog/2005/12/29/csv-file-lookup-with-http-request-and-response-in-xi
/people/william.li/blog/2006/04/18/dynamic-configuration-of-some-communication-channel-parameters-using-message-mapping
Regards,
Ashwin M
[Dont forget to mark the answers :)]
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Please dont send me the blogs ............
Reply only if u can directly help me....
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Hi ,
I have used these parameters for HTTP reciever adapter when connecting to Siebel :
You have to specify the following parameters in your receiver http adapter
Addressing Type : URL
Target Host : siebservdev (mention your HTTP server host name)
Service Number : 80
Path :/eai_enu/start.swe? SWEExtSource=SiebelUpsert&SWEExtCmd=Execute&UserName=SADMIN&Password=SADMIN (In the Path filed mention your query string.)
check this blog also...
/people/siva.maranani/blog/2005/09/15/push-data-to-mvc-architectured-application-using-xi
HTTP adapter returns status code 200.You can send the response back to the RFC basing on this status code.
Let me know if you need any further information.
Sekhar D
U can use the variable substitution to capture the URL string in the message, and configure the receiver channel accordingly,
The blog i m refering u is not the exact blog, but u can make out how to use variable substition from this article, and use accordingly in ur case:
/people/jayakrishnan.nair/blog/2005/06/28/dynamic-file-namexslt-mapping-with-java-enhancement-using-xi-30-sp12-part-ii
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Hey,
This link might help you.
http://help.sap.com/saphelp_nw04/helpdata/en/44/79973cc73af456e10000000a114084/frameset.htm
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