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help in Mapping.

Former Member
0 Kudos

Hi experts,

I have one sender attribute, its length is 264 Characters.

I have only one receiver attribute, its length is 72 Characters.

How I will map that sender attribute with this receiver attribute, so that the data should not be lost ?

Can we split sender attribute in 4 parts of 72 Characters and map that in receiver attribute ?

Regards,

Study SAP

Accepted Solutions (1)

Accepted Solutions (1)

Former Member
0 Kudos

Hi,

What is the occurrence of receiver attribute. If it is unbounded then what u can do is.

righ click on receiver attribute and say dublicate and dublicate it 4 times.

Now use the substring function. map first receiver attribute with 72 character using substring function, again use the substring function map anoth character from 73 to ... n so an..

one clarification r ur sender attribute will always contains 264 char data.

Chirag.

Former Member
0 Kudos

Hi chirag,

Thanks for you reply,

The occurance of receiver attribute is 0:1.

It is OK, we can use substring function, but this duplicate system is not clear to me.

Sender attribute is fixed for Maximum 264 Characters.

Regards,

Study SAP

Former Member
0 Kudos

Hi,

Unless and untill u are not making the receiver attribute to unbounded u can not use the dublicate function at the target element.

did u right click on receiver attribute and use the dublicate function.

confirm:

u can get value less that 264 or always 264 fixed value.

if u r receiving 144 value then do u need to create only two receiver node or there will be always 4 receiver attribute at target.

clarify it so that i can suggest u accordingly.

chirag

Answers (0)