on 03-12-2008 6:06 AM
i need define a job with sm36. The job must be executed current day and every 2 hours. i can't realize it. Could you help me? . It mentioned that the job exclude next day's time before the current defination's time.
pleas help me ,thanks very much!
SM36 -> Start condition -> Immediate -> tick the periodic job tab -> click on periodic values button -> Other period -> insert 2 in "hours"
Thats it.
Regards
Juan
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I don't see any clear relation to "Security", so will move the thread to "NW Administration".
Regards,
Julius
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it is not my means. for example: 3/13----3/14
00:00 02:00 04:00 06:00 -
10:00 12:00-----22:00.
no be included 08:00.
how i can define with one job?
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Hi,
In SM36, Select the immediately to run. After U click their periods & set Job period 2 hrs create.
Regards
Rajesh.
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Hi,
In SM36 once u entered job name & job class, then select the TAB - START CONDITION .There u can find relevent tabs according to ur requirement like for successor jobs or u can schedule for hourly also under PERIODIC values.U need to be very careful before u r sheduling periodic jobs.
Rgds,
Gadde.
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Hi,
Goto SM36, when you schedule a job, give the time every 2hrs from now..It will be executed.
Regards,
Sameer
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