Open model in a PopUp window

[Former Member]

Hi,

I have created a component which contain a button named 'open model'.

The buuton action is to open a model in a pop up window. This model is not part of my project but an external one.

I do not want to use a NonModel function.

What is the right code to do so?

Thanks,

Matan Barak

[Former Member]

Hi Matan,

I'm not entirely sure what you are trying to do here. My guess is that you want to replace the screen you are looking at with this pop-up window and return to it ones you are ready.

I would do the following:

• If you are using a component in another DC: Add the external component to the public part of the DC

• Add the external DC to the used DC list of the component

• Add the external component as a used webdynpro component.

• Create a view with a ViewContainerUIElement in the component where you want to use the external component.

• Add the window of the exernal component to the window in the using component.

The external window will now be visible in the component.

Jeschael

Edited by: J.V. Lebbink on Jan 31, 2008 7:43 AM -- Oeps maybe to short.

[Former Member]

Hi ,

Thanks for you answer but I need to open it as a model and a non model.

is ther ea was to do it?

thanks,

Matan

[Former Member]

Hi,

IWDWindow win = wdComponentAPI.getWindowManager().createNonModalExternalWindow(URL, title)

win.show();

Regards

Ayyapparaj