error in url

[Senthilprakash1]

Dear all,

When i copy pasted this url in my browser "http://<server>:<port>/XISOAPAdapter/ " note: gave my server and valid port id.

is comming as you are not authorized to view the content of the requested directory. why is this comming?

Edited by: senthilprakash selvaraj on Dec 27, 2007 3:29 AM

Edited by: senthilprakash selvaraj on Dec 27, 2007 3:30 AM

[Former Member · Accepted solution]

Hi,

It is coming since you are not authorized

Which user are you using to authenticate yourself?

Regards,

Sumit

[Senthilprakash1 · Accepted solution]

Dear all,

tell me this weather this above mentioned error will create any problem when i test a webservice to rfc scenario with the same id using a XMLSPY ?

Note: And whats the exact authentication i need for this in XI server.?

Regards,

prakash

Edited by: senthilprakash selvaraj on Dec 27, 2007 4:46 AM

Edited by: senthilprakash selvaraj on Dec 27, 2007 5:22 AM

[moorthy · Accepted solution]

Hi,

In RFC to WebService Scenario, I don't think any need of XML SPY over here. Just trigger the RFC and check the status in MONI, WebService. Provided you have configured the SOAP Receiver Channel correctly and WebService is available

Regd.. the url authorization try out with User ID PIDIRUSER and corresponding password,

Rgds , Moorthy

[Senthilprakash1 · Accepted solution]

Dear Krishnamoorthy,

Very sorry, i was talking about webservice to rfc scenario...!

my mistake i have chaged my query.

Regards,

Prakash

[moorthy · Accepted solution]

Oh...

If so just test it using XML SPY..Generally it doesnot give any error.

While testing it will ask user id and password. Then use PIAPPLUSER and corresponding password to test the SOAP to RFC scenario.

Hope your sender SOAP Channel configuration is right...

Be very careful while providing message servlet, port etc in the channel..

Are u getting any other error

Rgds, Moorthy

[Senthilprakash1]

Dear all,

When i copy pasted this url in my browser "http://<server>:<port>/XISOAPAdapter/ " note: gave my server and valid port id.

is comming as you are not authorized to view the content of the requested directory. why is this comming?

tell me weather this above mentioned error will create any problem when i test a webservice to rfc scenario with the same id using a XMLSPY (During Posting in sender side or anyware) ?

Note: And whats the exact authentication i need for this in XI server.?

Regards,

prakash

[nikhil_bose]

to test the web service you have to use

http://<server>:<port>/XISOAPAdapter/MessageServlet?channel=<party>:<service>:<channel>;

if you don't have party you can skip it, but not the ':'

You can try

http://<server>:<port>/XISOAPAdapter/MessageServlet

this will ask the user name and password.

user: PIAPPLUSER

thanks

nikhil

[Senthilprakash1]

What if i dont have access to the PIAPUSER user id ?

Wont my scenario work via XMLSPY..!

and yes the link which umentioned only i gave.

After that it asked for my server authentication, that time i gave my user id in which i created the scenario.

and i dont have access to PIAPUSER id.

Regards,

Prakash

Edited by: senthilprakash selvaraj on Dec 27, 2007 7:44 AM

Edited by: senthilprakash selvaraj on Dec 27, 2007 7:45 AM

[nikhil_bose]

your question is to access the url

http://<host>:<port>/XISOAPAdapter/ ?

PIAPPLUSER is a user with Application Role assigned.

to use XML Spy, your sender channel need to be exposed as a web service. you can do this from the Integration directory Tools -> Define web service. (notice that, this is related to your sender channel only).

Give the URL as

http://<yourhost>:<port>/XISOAPAdapter/MessageServlet?channel=:<yourservice>:<yourchannel>;

and provide the MI, Sender according to your sender channel.

now, it is exposed as web service. give the above created url in the XMLSPy and test it.

if it is not you expected answer, i may be mistaken your question, plz repost elaborately.

thanks

nikhil

[Former Member]

Hi Senthil,

Incase your userid doesnt work from XML Spy then you can ask your basis team to assign your user id the following role.

SAP_XI_APPL_SERV_USER

You will get the authorization once the role is assigned to your id.

Regards,

Sumit