on 09-24-2007 9:48 AM
Hi,
In my scenario
One source and three receivers are there
Source structure is;
Emp_no
Emp_name
Emp_cat
Emp_DOJ
Three receiver is having same structure as source.
If Emp_cat = A, then that particular record should move to First receiver
If Emp_cat =B , then that particular record should move to Second receiver
If Emp_cat =C,then that particular record should move to Third receiver
I given the condition in Receiver Detemination.
If there is only one record in source file then it is moving to particular receiver based on Emp_cat.
But if there are multiple records with different Emp_cat(A, B, C) all records are moving to all three receivers.
As i am new to XI, can anyone tel me steps to achieve the above result with multiple records in source file.
Regards
Prakash
Hi Prakash,
Create a context object by the name EMP_cat. In the Message Interface go the Context tab and assign that context object to ur field. Rest is the same in Design. Coming to configuration, in receiver determination step, after u assign the business service, click on condition and select context object and assign value (i.e. A, B, C)
There is no need to use BPM in this case.
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you have to use enhanced receiver determination concept to achieve ur scenario.
u should maintain the conditions in the mapping itself.
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Hi,
You have to go for BPM for this ,
you can send splitted records to different receivers.
it has to be handeled in mapping in BPM.
Regards,
Akshay.
Reward points if find useful.
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use conditional routing in receiver determination.
ref:
/people/shabarish.vijayakumar/blog/2006/06/07/customise-your-xpath-expressions-in-receiver-determination
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