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Naming a file in File(Sender) communication channnel

Former Member
0 Kudos

Hi ,

I am working on File to Idoc scenario.

I need to define the file name in the communication channnel.

The input files would be in incremental format as below,

DRX.XYZ.B46.LOCLPUR.R006.DATA

DRX.XYZ.B46.LOCLPUR.R006.DATA.G0226V00

DRX.XYZ.B46.LOCLPUR.R006.DATA.G0227V00

DRX.XYZ.B46.LOCLPUR.R006.DATA.G0228V00

DRX.XYZ.B46.LOCLPUR.R006.DATA.G0229V00

DRX.XYZ.B46.LOCLPUR.R006.DATA.G0230V00

How can i define this file name in the communication channel. Please advise.

Regards,

Manoj

Accepted Solutions (1)

Accepted Solutions (1)

Former Member
0 Kudos

Hey,

As suggested u can use characters <b>(*, ?)</b> While specify the file name.

( <b>*</b> ) STAND FOR A STRING.

( <b>?</b> ) FOR A SINGLE CHARACHTER.

So as already suggested DRX.XYZ.B46.LOCLPUR.R006.DATA * should work fine.

Post bak the results.

<b>Cheers,

*RAJ*

*REWARD POINTS IF USEFULL</b>*

Answers (3)

Answers (3)

Former Member
0 Kudos

I used only the file name.

Former Member
0 Kudos

Dynamic File Name Part 1

/people/jayakrishnan.nair/blog/2005/06/20/dynamic-file-name-using-xi-30-sp12-part--i

Dynamic File Name Part 2

/people/jayakrishnan.nair/blog/2005/06/28/dynamic-file-namexslt-mapping-with-java-enhancement-using-xi-30-sp12-part-ii

Mudit

Shabarish_Nair
Active Contributor
0 Kudos

provide your file name as

DRX.XYZ.B46.LOCLPUR.R006.DATA.