on 05-08-2016 1:36 PM
Hello Experts,
Can somebody provide me the screenshot of working inboundRA which is connecting to multiple ECC systems, i want to know how multi-repository is configured.
Pleas no documents please i have gone through documents , i need screenshots.
Thanks in Advance.
Kiran
Hi Kiran,
You can find below screen shot of multi repository configuration.
You need to configure like below (SID = XI_IDOC_DEFAULT_DESTINATION_SID)
CRD=XI_IDOC_DEFAULT_DESTINATION_CRD;EWD=XI_IDOC_DEFAULT_DESTINATION_EWD;E6D=XI_IDOC_DEFAULT_DESTINATION_E6D;
And you need to create all of the above RFC destinations in NWA destinations which are pointing to respective systems.
Regards,
Praveen.
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Hello Kiran,
Resource Adapter Update
NetWeaver Administrator > Configuration (Konfiguration) > Infrastructure (Infrastruktur) > Resources (Anwendungsressourcen)
Then look for Resource Adapter inboundRA and there go to tab Properties (Eigenschaften) and check property multiRepository. There you should find values like System_Name=XI_IDOC_DEFAULT_DESTINATION_System_Name;-> If you don't find new system there then it's not yet configured so you must create new destination and add that string here.
NetWeaver Administrator > Configuration (Konfiguration) > Infrastructure (Infrastruktur) > Destinations (Destinationen)
Here you create new destination called XI_IDOC_DEFAULT_DESTINATION_System_Name (as you reference from resource adapter) with the parameters provided by client for given system.
Hope this is what you are looking for..!!
Regards
S Tomar
Hi Praveen,
in the screenshot you have configured Destination name = XI_IDOC_DEFAULT_DESTINATION where as this value is not configured for multirepository ? may i know to which system does this rfc: XI_IDOC_DEFAULT_DESTINATION points to your system ?
and i have read few blogs where is tells multireposiroty should not be configured manully the value gets entered to this property as soon as you start and stop the sender idoc_aae channel ?
But i believe for first time we need to configure this manually ? correct me if i am wrong.
Thanks.
Kiran
Hi Kiran,
Regards,
Praveen.
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