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SAP TM Incompatibilities

Former Member
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Hello Gurus,

We have following product group and MOT group incompatibilities.

Is given is the correct way of modelling scenario with  3 definitions and 6 conditions?

Regards,

Gupta

Accepted Solutions (0)

Answers (1)

Answers (1)

former_member182454
Participant
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Hi,

Yes Agree. Make sure to use the conditions using the BRF plus table with the combinations you had speciifed.

Former Member
0 Kudos

Hello Indraneel,

Thank you for your response!

I have following questions regarding incompatibilities

- How system interprets evaluation results in conditions and incompatibility definitions.

Scenario1:

Condition5

Condition6

Product

  1. Evl.Result

MOT

  1. Evl.Result

FRUITS

1

CHILLED

1

FLOWERS

1

DRY

1

Defination3

  1. Evl.Result

  1. Evl.Result

Condition5

1

Condition6

1

If FU is with fruits Evl.result would be 1 form condition5 and for MOT – Chilled Evl.result would be 1, then control goes to definition and finds 1 & 1 are incompatible, so now incompatibility evaluation decides FRUITS are incompatible with CHILLED MoT.

Sceanrio2:

FLOWERS can go into CHILLED but can’t go into DRY

FRUITS can’t go into CHILLED but can go into DRY.

Defination3

Condition5

Condition6

Product

  1. Evl.Result

MOT

  1. Evl.Result

FRUITS

1

CHILLED

0

FLOWERS

1

DRY

1

Defination3

  1. Evl.Result

  1. Evl.Result

Condition5

1

Condition6

1

- If FU with FLOWERS Evl.result would be 1 form condition5 and for MOT – CHILLED Evl.result would be 0, then control goes to definition and finds 1 & 1, then decide FLOWERS can go into CHILLED.

- If FU with FLOWERS Evl.Result would be 1 from condition5 and for MOT – DRY Evl.result would be 1 then control goes to definition and finds 1 & 1, then decides FLOWERS can’t go into DRY

Yes, above two results are as required by the business.

When it comes to Fruit

- If FU with FRUITS Evl.result would be 1 from condition5 and for MOT- CHILLED Evl.result would be 0, then then control goes to definition and finds 1 & 1, decides FRUITS can go into CHILLED

- IF FU with FRUITS Ev.Result would be 1 from condition5 and MOT-DRY Evl.result would be 1, in definition Evl.result is 1 & 1, decides FRUITS can’t go into DRY, but business case is - FRUITS can’t go into CHILLED

Possible solution:

Create a new set of conditions and definition as below

FLOWERS can go into CHILLED but can’t go into DRY

Defination3

Condition5

Condition6

Product

  1. Evl.Result

MOT

  1. Evl.Result

FLOWERS

1

DRY

1

Defination3

  1. Evl.Result

  1. Evl.Result

Condition5

1

Condition6

1

FRUITS can’t go into CHILLED but can go into DRY.

Defination3

Condition7

Condition8

Product

  1. Evl.Result

MOT

  1. Evl.Result

FRUITS

1

CHILLED

1

Defination3

  1. Evl.Result

  1. Evl.Result

Condition5

1

Condition6

1

Question:

  • If above said is the solution for scenario two, we might end up creating huge number of conditions and definition…is there any other way to reduce effort

Regards,

Gupta

former_member182454
Participant
0 Kudos

Hi,

Kindly check this discussion thread as enclosed in the attachment since I am not been able to copy paste the thread.

Kindly let me know if this is requires further clarification.

Basically you can enter one condition and select the values-       Identical values only and in this way you can define an incompatibility between two instances of same business object.Also to group together No of conditions you can group multiple combinations using incompatability type.