How to display even and odd number ranges between two given inputs.

[Former Member]

Hi Every one,

I am just started my career in sap abap and trying to find the solution for this.

I am trying to display number range using select options, but I am getting an error "Memory low leave the transaction before taking a break".

Example: when I give two number 2 and 10 , it should display set of all even and odd numbers in that range.

Below is the code logic that I am using:

data: a type i,

         b type i,

         c type i,

         d type i,

         num type i.

select-options: in for num.

a = inp-low.

b=inp-high.

c = inp-low mod 2.

d = inp-high mod 2.

while a <=b and c = 0.

write: "even numbers:', a.

b = a + 1.

endwhile.

while a <=b and c <> 0.

write: "odd numbers:', b.

b = a + 1.

endwhile.

Any help will be much appreciated.

[PeterJonker]

Debug your code and see what is happening. It will definitely give you a clue. It has to do with statement C <> 0.

[Former Member]

Hi

this is an infinite loop:

while a <=b and c = 0.

write: "even numbers:', a.

b = a + 1.

endwhile.

because a is alway less than b

Max

[Former Member]

Sorry, can you give me some clue on the logic to be used to resolve the infinite loop.

[Former Member]

This is your logic...changed:

data: a type i,
          b type i,
          c type i,
          d type i,
          num type i.

 data: even type i,
       odd  type i.

 select-options: in for num.

 a = in-low.
 b = in-high.

 c = a mod 2.

 if c is INITIAL. "It measn a is even
   even = a.
   odd  = a + 1.
 else.
   odd  = a.
   even = a + 1.
 endif.


 * Even
 a = even.
 while a <= b.
   write: / 'even numbers:', a.
 *  b = a + 1.
   a = a + 2. "The next even number
 endwhile.

 * Odd
 a = odd.
 while a <= b .
   write: / 'odd numbers:', a.
   a = a + 2. "The next odd number
 endwhile.

[Former Member]

Thank you so much for your help, I am not familiar with debugger yet, will learn soon.

I hope to develop logical thinking soon.

All the replies are much appreciated.

[Former Member]

Hi

In this situation you don't need to use the debbuger, it's enough to know a little bit of mathematical logic, you r program was not right in certain step:

- Set the limit of your interval: this step is ok

a = in-low.
b = in-high.

- You should know if the range starts with even or odd number, so to use statament MOD is right:

c = inp-low mod 2.

Ther result will be 0 if lower limit is even, so this step should be use to know which kind of number is INP-LOW

If A is even, the next even number will be A + 2, or the next odd number will be A + 1: it's the same, it depends on you wan to calculate, so your code:

while a <= b and c = 0.
write: "even numbers:', a.
b = a + 1.
endwhile.

it's not ok, because:

- b will be a odd number (because it's the next one of even number)

- the loop will be infinitive, because you a (and so b) will be always the same and so a will be alway less than b, you should increase a instead of b, so your code should be:

while a <= b and c = 0.
   write: "even numbers:', a.
   a = a + 1.
endwhile.

but a = a + 1 will return all integer number between your range, if you want to know only the even one you need to increase a of 2:

while a <= b and c = 0.
   write: "even numbers:', a.
   a = a + 2.
endwhile.

the same considerations are valid for odd number calculation

Max

[Former Member]

Thank You so much for this analysis.

I greatly appreciate your help.

[matt]

Check the structure and usage of select options. If someone enters 1 to 10 in the select option, the select option (which is an internal table with a header line) will contain this:

I BT 1 10

and your program will work (once fixed!).

But what if they enter an exclusion?

E BT 1 10

This means "give me all numbers excluding the numbers 1 to 10".

Or start using GE or LT?

I LT 10.

If you want user input that is only to be used as range then you should use two parameters, rather than a select-option.