on 12-05-2013 3:13 PM
Hi guys, how are you?
now, when i'm getting the wsdl over Integration Builder, i'm getting this on location for HTTP_PORT: http://host.mycompany.com
but we want that the url location be the LB url: http://piqa.mycompany.com
we was editing some parameters on Exchange profile on Administration on PI. but it doesnt' work, still it generate http://host.mycompany.com
these are the parameter we have edited.
com.sap.aii.connect.repository.name & com.sap.aii.connect.repository.httport.
Could you help me pls?
Regards.
Hi Yassir,
If you are providing the web service to other system to invoke PI service, then you need to edit the WSDL after downloading from Integration Builder.
your service should in below format
http://host:port/XISOAPAdapter/MessageServlet?channel=party:service:channel
Regards,
Harish
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi Harish, while we use this format:
http://host.mycompany.com:50200/dir/wsdl?p=ic/7d48bd0429343b6d8c7aa05416c811bc
the wsdl it's displayed well on SOAP UI, but the location on HTTP_PORT is still http://host.mycompany.com.
when we use this format
http://PIQA.mycompany.com/XISOAPAdapter/MessageServlet?channel=party:service:channel
=>
we have this error
Thanks for your answer.
Regards.
Hi Yassir,
you are missing the port when you use the other format.
when we use this format
http://PIQA.mycompany.com/XISOAPAdapter/MessageServlet?channel=party:service:channel
=>
The correct format should be
when we use this format
http://PIQA.mycompany.com:50200/XISOAPAdapter/MessageServlet?channel=party:service:channel
=>
Hope this help
Harish
Hi the url http://piqa.mycompany.com is a load balancer url and the port is 80.
this url forwards to http://myhos.mycompamy.com:50200/....
that's the point..
Regards.
User | Count |
---|---|
87 | |
10 | |
10 | |
10 | |
7 | |
6 | |
6 | |
5 | |
5 | |
4 |
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.