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How to extract the java class from SCA file in web dynpro java

susmita_panigrahi
Active Participant
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Hi

For User Admin tab in SAP portal the corresponding WDJ application is sap.com/tc~sec~ume~wd~umeadmin .This DC is not available in our project NWDI. Basis tem provide us the SCA file UMEADMIN12_0-10006669.SCA . When we open this file in ZIP we get the tc~sec~ume~wd~umeadmin.sda file.

Can you please provide us information without using NWDI can we see the java class file code used in the SCA file or .SDA file?

Thanks & Regards,

Susmita

Accepted Solutions (1)

Accepted Solutions (1)

susmita_panigrahi
Active Participant
0 Kudos

Hi

Closing this thread.I have installed WinRAR software to see the SCA file in ZIP format.

Thnaks,

Susmita

Answers (2)

Answers (2)

vijay_kumar49
Active Contributor
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SCA is a zip format file, so use winzip or any other unzip tools to extract it.

susmita_panigrahi
Active Participant
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Hi Vijay,

After un zip the >SCA file I received the .JAR file sap.com~tc~sec~ume~wd~umeadmin~UmeAdminComp.JAR .

Can you please provide the information how to Extract the JAR file to see the java classes inside it?What is the tool name to decompile JAR file?

Thanks,

Susmia

vijay_kumar49
Active Contributor
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Right click on Jar file and click on extract here...

junwu
Active Contributor
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you want see content of the class file or just want to see the class files with your eye

if former, http://code.google.com/p/innlab/downloads/detail?name=jd-gui-0.3.3.windows.zip&can=2&q=

junwu
Active Contributor
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just unzip it