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macro error : layoutvar_value

former_member566355
Participant
0 Kudos

Hi,

I am using the mentioned function in a macro.

The syntax writtne is as given below -

step 1 -

      layoutvariable_set ( 'x1' ; 100)

step 2 -

      results cell: Quantity (29.03.2013) =

      layoutvar_value ( 'x1')

When consistency check is done, it is giving the following error -

'Incorrect assignment Expression missing Operand Missing'

I tried

               step 2 -

                     results cell: Quantity (29.03.2013) = 100

to pinpoint the error line. In this case error is not coming.

Regards,

RS

Accepted Solutions (0)

Answers (1)

Answers (1)

former_member187488
Active Contributor
0 Kudos

Hello,

For step 2, the "layoutvar_value ( 'x1')" should be created in the next level of "results cell: Quantity (29.03.2013) =", as:

step 2 -

      results cell: Quantity (29.03.2013) =

           layoutvar_value ( 'x1')

Not sure whether this addresses your issue.

Best Regards,

Ada

former_member566355
Participant
0 Kudos

Hi Ada,

Thanks for the reply.

I am not quite clear with difference between the syntax I have written and what you have mentioned ?

Could you please be more specific ?

What will be the 'next level'  ..action box ?  or  something else ?

Regards,

RS