on 01-30-2013 8:25 PM
Hello Experts,
We have a synchronous interface SOAP (initiator) to RFC and back to SOAP. We are supposed to get an encrypted credit card number from RFC in the Response payload. And, we have to decrypt that Credit Card number in PI ESR mapping and only send last four digits back to the calling system. We are gonna be provided with a decryption key by the ECC team. My question was how to use this decryption key in PI ESR mapping to decrypt the credit card number. Do I need a dedicated Java code to achieve this or is there an existing function in PI to do this? You answer is much appreciated.
Thanks.
No Standard function available for this, now a days this type of things coming very frequently. please update SCN about your final solution.
regards,
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Yes you need java mapping or some UDF to handle this. You could see this link for the custom algorithm as a starting point... The site uses AES algorithm for the encryption.
http://www.code2learn.com/2011/06/encryption-and-decryption-of-data-using.html
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Patel,
>>> My question was how to use this decryption key in PI ESR mapping to decrypt the credit card number. Do I need a dedicated Java code to achieve this or is there an existing function in PI to do this?
You need to go for Java code..
Cheers
Agasthuri
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi Mayur,
You have to check with ECC team for encryping/decryption algorithm. Check if it is open standard encryption/decryption algorithm and if so there should be some standard java API's already available. Otherwise you have write custom algorithm in java (UDF) to decrypt the content.
Regards,
Praveen Gujjeti
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
User | Count |
---|---|
89 | |
10 | |
10 | |
10 | |
7 | |
6 | |
6 | |
5 | |
4 | |
3 |
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.