on 09-06-2006 7:03 PM
hi,
i want to connect to SAP using JCO and the following user:
login: testuser
password: foo"bar
I get LOGON_FAILURE. I have already tried to escape the quotation with \" and with
\" but nothing works.
Help would be appreciated:)
thanks
best regards
simon:)
Hi Simon,
you can try the URLEncoder.encode method. See link below with example.
<a href="http://www.javapractices.com/Topic96.cjp">URL Escape</a>
I wouldn't recommend using such characters in passwords though. Maybe you should try and change the password.
regards,
Dion
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Hello:)
Thanks for the reply. However, I have already tried to mask,encode etc. this password, everything failed.
I have read some posts about the ", that if it is found in the passwd, the passwd ist cut off at that position.
I have also read something about qouting whole passwords when they contain question marks or sth.(e.g. "foo?").
Those are my assumption only. I have not found any definite answer, so I am still looking.
any help is more than welcome:)
best regards
simon:)
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