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[former_member224727]

We having unique requirement for result revording valuation.

Our business measure char of medical equipment and record in system. At the time of recording they record value for two equipemnt and if diff is leass than 0.5 then pass otherwise fail. Please suggest solution.

Reply appreciated.

[anand_rao3 · Accepted solution]

Hi Tom,

Why canu2019t you use calculated characteristic here? I try to explain.

1. Your inspection plan should contain 3 MICs. First 2 MICs should be same. E.g Length

0010 u2013 MIC1

0020 u2013 MIC1

0030 u2013 MIC3

2. Set MIC3 for calculated characteristic in control indicators.

3. In inspection plan when you try to assign MIC3, system will ask you to put formula. The formula should be (A00010-A00020)

4. When you record reading for equipment 1, record it against MIC1. For second equipment record its result against MIC2.

5. Valuate both these MICs

6. Now select 3rd MIC and click on u201Cvaluate formulau201D icon

7. System will automatically calculate difference of above readings

8. Keep tolerance values 0.5 so that whenever reading is exceedind 0.5 range it will valuate it as REJ.

Try this if works for you!

Regards,

Anand Rao

[former_member42743 · Accepted solution]

I think a calculated characteristic can work. Anand has a good suggestion. Here's another approach you can try since you only have two values.

Set up Characteristic A (0010) for indiviudal results recording with a fixed sample size of 2. Thus you always have to record two resutls.

Set up Characteristics B, variance of A, (0020) as a calculated characteristic.

Try formula CA0010 - C90010. (maximum value of characteristic - minimum value charateristic)

If you use physical samples it might be BA0010 - B90010, (maximum value of sample - minimum value sample)

For the calculated characteristic the spec would be 0.0 - .5

FF

[Former Member]

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