on 02-22-2011 1:48 AM
Dears,
For example, a piece of component A (material A) can be assembly to 6 pieces of material B (BOM B), because 1/6 is a infinite decimal, so we may define assembly quantity in BOM B to 1/6=0.166667 for consuming material B.
But this will make logical consuming quantity of component A bigger than physical consuming quantity. (0.166667 > 0.166666666...)
It becomes 1 piece of component A is not enough to assembly to 6 pieces of material B in SAPME.
Even we define assembly quantity in BOM B to 0.166666, it become always left a little bit of component A in logical data.
The logical and physical data are always not equal.
How to handle this kind of problem in SAPME?
Thanks!
Sergiy
Why don't you simply multiply each and every by 6? Then you will have Lot Size for comp A = 6 and Assy Qty for BOM B component = 1. And still you will be able to assembly 1 SFC of A into 6 SFCs of B.
Regards,
Sergiy
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi,
Maybe it would be possible for you to track component A inventory unit under 1 inventory id but with qty 6? This way you can assemble qty=1 into each of 6 B units. And inventory ID of comp A used will be the same.
Konstantin
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi,
Thank you for your information.
I think we should define lot size of material depends on its count unit.
Because our case is a sheet(component unit) of component assembly to a base material which to be cut to 6 pieces(manufacturing material unit).
And our customer will count 100 sheets (600 pieces) as a carrier unit during processing. (a SFC)
So actually we define the base material lotsize=600, assembly qty=0.166667 for component consuming. Every 6 pieces of base material needs assembly a sheet of component.
It's more reasonable for our case.
But needs to resolve the infinite decimal problem.
Thank you.
User | Count |
---|---|
99 | |
9 | |
8 | |
5 | |
4 | |
3 | |
3 | |
3 | |
3 | |
3 |
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.