on 11-19-2010 4:55 AM
Dear All,
I've developed a mobile app for Handheld.
I want to create a button in the Mobile App, when user click on this button, it should close the current mobile application and take the user to Application Launcher page.
Please let me know how this can be done.
Note: I'm using SAP Mobile 7.1 and SAP NetWeaver 7.1 Composition Environment SP09 PAT0002
Thanks in advance,
Ajay
Edited by: Ajay Sharma on Nov 19, 2010 5:55 AM
I think your best chance is to investigate the WDL class if you are talking about the PDA
Drill down with NWDS on classes that you think might be responsible for navigation.
If SAP developer can help on how to use the "launchApplication" method, what arguments to provide...?
http://help.sap.com/javadocs/nwmobile/SP3/index.html
I know I have been asked to make larger buttons for users who have trouble using stylus or we needed to hide Menu button altogether for security/"prevent user from messing up the client", but we put that requirement out of scope.
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Hi Ajay
try doing the following
1. Create an outbound plug on the window, say 'Exit'
2. Now create an outbound plug on the default interface view by the same name 'Exit'
3. Include the window and the interface as a part of 'Required controllers' in the references part of the view
4. Now create a button called 'Exit' in the view and fire an action on it
5. In the action just fire the 'Exit' button of the Window
Eg: wdThis.wdget<window controller>.wdFire<Exit Plug>
Hope this helps
Best Regards
vaidehi
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Hi,
All UI functionalities exposed by the client framework to the application code is done using WDLite class.
You can use it to us do something with the framework like exit an application.
Regards,
Nipun
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Hi Ajay,
in Handheld application, if you need to navigate to the application launcher, you can directly navigate through the menu->System->Application Launcher.
Users can navigate to the Application launcher any time.
No need of implementing this in the application.
Thanks and Regards,
Suma
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