Determine last position

[Former Member]

Hi,

in XSL mapping I have following command: position()=last()

It returns the last apperance of a given node.

Is there any simple soloution to do the same in graphical mapping?

Thanks

Chris

[Former Member · Accepted solution]

Thanks for this information

[jyothi_anagani · Accepted solution]

Hi Christian,

Map like this..

input---->UDF---->output

While writing the UDF select Context

UDF code..

result.addValue(a[a.length - 1]);

This is working.

I have tested.

Check it...

Thanks.

[Former Member · Accepted solution]

Hi Jyothi,

awesome. It really works that simple.

My problem was that I have to check if the grandfather node is the last one:

main node

-->node to check (occ 1..n)

-

---

> node (occ 0..1)

-

---

> field

But because the field is (of course) also in a context and the direct parent node could

only appear once at least, it works

Thanks.

Points for you.

Edited by: Christian Riekenberg on Aug 27, 2009 3:45 PM

[former_member181962]

Hi Christian,

You can try the following.

check this image which shows how i did it using graphical mapping:

http://www.flickr.com/photos/41818237@N02/3862193420/

Regards,

Ravi

[MichalKrawczyk]

hi,

>>>Is there any simple soloution to do the same in graphical mapping?

I don't think so - you need to write an UDF to handle it

Regards,

Michal Krawczyk