on 08-11-2009 3:18 PM
Hello,
How do I determine the mode (synchronous/asynchronous) when I create a proxy? I am trying to create an asynchronous inbound proxy and when I hit "generate" in SPROXY I get a synchronous proxy.
Thanks,
Matt
hi,
>>>How do I determine the mode (synchronous/asynchronous) when I create a proxy?
you can only determine it in repository (or ESR)
your message interface or service interface must be asynch and not sync over there
Regards,
Michal Krawczyk
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi Matt,
Do you know the reason why when the fault message take out, it will generate as Asynchronous?
I used to generate as Asyn when I have the fault message, but Now I cannot.
Regards,
Nattawat
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
You guys are right. But I had already selected Asynchronous and it was still creating a Synchronous proxy. But I had a FaultMessage defined and once I removed the fault message it allowed me to create it as an asynchronous inbound proxy.
Thanks,
Matt
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi mathew ,
How do I determine the mode (synchronous/asynchronous) when I create a proxy? I am trying to create an asynchronous inbound proxy and when I hit "generate" in SPROXY I get a synchronous proxy.
---> As per the requirement you have to create sync/async interfaces at ESR/IR in XI .Those interfaces only gets reflected in SPROXY at application server. So the type of interface you have created at XI according to that only you get the proxy in application server .
Regards,
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
Hi,
Your Message Interface in XI decides whether proxy is synchronous or asynchronous.
When you generate proxy corresponding to some MI, Its mode decides the synch or asynch.
Regards,
Anurag Garg
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.
User | Count |
---|---|
92 | |
11 | |
10 | |
9 | |
9 | |
7 | |
6 | |
5 | |
4 | |
4 |
You must be a registered user to add a comment. If you've already registered, sign in. Otherwise, register and sign in.