on 05-04-2006 4:08 PM
Hi All,
Could anybody help me to solve my problem?
In web Dynpro I wand to create a page with a list of URL.
I want to click on a URL. Then the page will be opened on
the same existing page not as a popup window. Then I want to come back to the main page(where the URL list
exist). How is it possible?
Could anybody help me by giving suggestion and codding?
Thanks & Regards
Sudip
Hi Sudip,
Just use LinkToURL UI element with appropriate "reference" property and "target" property set to "_self".
Best regards, Maksim Rashchynski.
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Hi Maksim,
Just use LinkToURL UI element with appropriate "reference" property and "target" property set to "_self".
after clicking link URL, another window opens, but following error
500 Internal Server Error
SAP J2EE Engine/6.40
Application error occurred during request processing.
Details: com.sap.tc.webdynpro.services.sal.api.WDDispatcherException: Requested deployable object 'local/Test' and application '_SELF' are not deployed on the server. Please check the used URL. The ID of this error is
Exception id: [001143E75E1700490000003000004E84000412FB2BBC3800].
1) Even me to have a requirement
after cliking link to URL, it should open another window,but where should i mention the URL 1)if i want to open www.yahoo.com
2) In case i want to open another view which consists of few UI elements ( one way is popup window) without using pop window is it possible to acchive this by using Link to Action or Link to URL UI Element.
Thanks in Advance
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