Table Entry Insert - Java Programming Question

[Former Member]

I design table input/output interface with adding / deleting entry function. Table data will be saved in AbstractList by BAPI.

In Controller implementation tab, I created "input" under WD_init()

Bapi_Entrysheet_Create_Input <b>input</b> = new Bapi_Entrysheet_Create_Input();

wdContext.nodeBapi_Entrysheet_Create_Input().bind(<b>input</b>);

<b>input</b>.setEntrysheetheader(new Bapiessrc());

In view action function, I need "input" as.

input.addEntrysheetservices(new Bapiesllc());

My question is how I can let view class know "input".

Thanks.

Message was edited by: li dong

Message was edited by: li dong

[former_member182372 · Accepted solution]

Hi li dong,

You need to establish context mapping between view and controller. Open view, select "Properties" tab, In "Required Controllers" section press "Add" and add your controller. Create model node in view (Bapi_Entrysheet_Create_Input) and click "Edit context mapping" in context menu for node. Establish context mapping. Than you can call

wdContext.nodeBapi_Entrysheet_Create_Input().modeObject().addEntrysheetservices(new Bapiesllc());

from view.

Best regards, Maksim Rashchynski.

[Former Member]

Maksim,

Thanks for your reply. I reward you 2 points.

Your program only works in Controller and will not work in View.

I solve my case by createElement and addElement function.

Dong