on 05-26-2009 7:57 AM
hi experts,
i have date in following format
20090522
i want to change in
2009.05.22
please suggest me.
thanks
babbal
Hi,
Try this
DATA : DATE TYPE CHAR10.
CALL FUNCTION 'FORMAT_DATE_4_OUTPUT'
EXPORTING
DATIN = '20090522'
FORMAT = 'YYYY.MM.DD'
IMPORTING
DATEX = DATE
.
WRITE : / DATE.
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Hi,
Take one variable.
data : date type c(10).
lv_date = 20090522
concatenate lv_date0(4) lv_date4(2) lv_date+6(2) into date separated by '.'
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Hi
Use the following...
data : DATE1_1(10) type c,
DATE1 type d.
WRITE DATE1 TO DATE1_1 YYYY.MM.DD .
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data: lv_date_new type c length 10.
concatenate sy-datum(4) '.' sy-datum+4(2) '.' sy-datum+6(2) into lv_date_new.
write lv_date_new.
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