Need only the last 7 characters from string

[Former Member]

Hi

I have some strings that i have to process and i only need the last 7 characters out of each one.The problem is that those strings have different length each time.Is there any offset function that can help me or how can i do this in the easy way.I would not want to count the length of the string each time to process it using offsets

thanks

[Former Member · Accepted solution]

Hi,

Try this, hope it will solve ur problem .

x(3) type c.

strn = ''aaaa aaa aaa''

x = strlen( strn ) .

x = x - 7.

strn2 = strn+x(7).

[Former Member · Accepted solution]

Hi

First of all thanks for the fast response.

I have tried with this code:

data: str(20) type c.

LOOP AT gt_lips INTO gs_lips.

str = strlen( gs_lips-vgbel ).

if str > 7.

str = str - 7.

gs_lips-vgbel = gs_lips-vgbel + str(7).

endif.

modify gt_lips from gs_lips.

ENDLOOP.

but at this line: gs_lips-vgbel = gs_lips-vgbel + str(7). the program fails.I do not know why it fails.

[Former Member · Accepted solution]

Your Code :- gs_lips-vgbel = gs_lips-vgbel + str(7).

Correct code :- gs_lips-vgbel = gs_lips-vgbel+str(7).

Try to remove spaces in ur program between gs_lips-vgbel and + and str(7).

Edited by: vijetasap on May 14, 2009 12:06 PM

[Former Member · Accepted solution]

Use the following. Dont use str instead use x.

data: x(3) type c.

LOOP AT gt_lips INTO gs_lips.

str = strlen( gs_lips-vgbel ).

if x > 7.

x = x - 7.

gs_lips-vgbel = gs_lips-vgbel+x(7).

endif.

modify gt_lips from gs_lips.

ENDLOOP.

Hope it will solve ur problem.

[Former Member · Accepted solution]

Thanks a lot everybody ,it worked.

[Former Member · Accepted solution]

Hi,

Try this..

LOOP AT gt_lips INTO gs_lips.
str = strlen( gs_lips-vgbel ).
if str > 7.
str = str - 7 - 1.  " now you get the last 7 char
" The sum of position and offset should not be greater than field length
gs_lips-vgbel = gs_lips-vgbel + str(7).        
endif. 
modify gt_lips from gs_lips.
ENDLOOP.

[Former Member]

Hi,

try this:

DATA: STR TYPE STRING.
DATA: STRL TYPE I.
*
STR = '0123456789abcdefg'.
STRL = STRLEN( STR ).
*
IF STRL > 7.
  STRL = STRL - 7.
  STR = STR+STRL(7).
ENDIF.
WRITE: / STR.

regards, Dieter

[Former Member]

Hi,

Use class CL_RECA_STRING_SERVICES method RIGHT and indicate the number of characters you want to get from the right (=7) as below.

CALL METHOD cl_reca_string_services=>right

EXPORTING

id_string = my_string

id_length = 7

RECEIVING

rd_string = my_last_7_chars.

Hope this will help you.

Issa

[Former Member]

Hi,

You use STRLEN to count the length.

Lets suppose a variable v_var of length 10.

DATA: v_var type char10,

v_var1 type char7,

v_len type i.

v_var = 'ABCDEFGHIJ'.

v_len = strlen( v_var ).

v_len = v_len - 7.

if v_len < 0.

v_len = 0.

endif.

v_var1 = v_var+v_len(7).

Hope this resolves ur query.

Regards,

Nikhil

[Former Member]

Hi,

Refer the following program with string length calculation.

data:
 w_string type string,
 w_string1 type string,
 w_off type i value 0,
 w_off1 like w_off.

 w_string = 'vjhsdfahdfseht'.
 w_off = strlen( w_string ).
 w_off1 = w_off - 7.
 w_string1 = w_string+w_off1(7).
 write:
  w_string1.

Thanks,

Nithya

[Former Member]

Hi,

Do like this...

parameter : s(100).
CALL FUNCTION 'STRING_REVERSE'
  EXPORTING
    string          = s
    lang            = 'E'
 IMPORTING
   RSTRING         = S
 EXCEPTIONS
   TOO_SMALL       = 1
   OTHERS          = 2
          .
S = S+0(7).
CALL FUNCTION 'STRING_REVERSE'
  EXPORTING
    string          = s
    lang            = 'E'
 IMPORTING
   RSTRING         = S
 EXCEPTIONS
   TOO_SMALL       = 1
   OTHERS          = 2
          .
WRITE S.

Regards

Debarshi