on 04-20-2009 2:14 PM
Hi All,
I have a scenario like this.
There are two mappings. There is a one condition while genearying the root element of the first mapping. If this condition is not satisfies the first mapping will fail. If this mapping fails i want to trigger another mapping.
How to achieve this functionality.
If it is possible with BPM. how to call the second mapping in the BPM.
Hi
you can use the following steps in BPM.
Receive-->switch-->send
this is an example.
in the first branch of switch call first mapping and in secong branch call another mapping.
if the condition failsin first branch it will move to the second branch.
Thanks
Rinku Gangwani
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Create a block step.
IN the block step, create a transformation step, which holds your first mapping.
In the exception branch of the block step, have your second mapping in a transformation step.
Regards,
Ravi Kanth Talagana
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Hi Ravi,
My first mapping is synchronous mapping and second mapping is asynchornous mapping.
I am not able to call the sychronous mapping the transformation step.
I have done like below
Receive-Block->Sendschronoussend asynch(these two steps are in success branch)>Transformationstep-send Asynch(these two steps are in exception branch of block)--stop the BPM
but i am not able to execute the second mapping if first mapping fails
Hi
you can not create the containter for the synchronous interfaces.
you have to craete the two asysnchronous abstact interfaces .
thenusing those two abstract interfaces you have to define the containers in the BPM.
and you also have to define the interface mapping b/w those two abstract interfaces.
once you define the interface mapping you will be able to select the interface mapping using the transformation step in BPM.
once you select the interface mapping in BPM then you will be able to selece the interfaces
if you still face the problenm please reply me back.
Thanks
Rinku Gangwnau
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