on 12-27-2008 2:40 PM
Hi all,
I have created a SOAP-XI-File Scenario. I have tested it from XML Spy but my final target is to access the WSDL from Visual composer or web Dynpro JAVA.
So what would be the WSDL URL. I have tried with
http://<Host>:50000/XISOAPAdapter/MessageServlet?channel=:<Business Service>:<Sender CC>
but it is not working.
can you plaese help me.
Thanks in advance
Chandan
Edited by: Chandan Jash on Dec 27, 2008 3:42 PM
Edited by: Chandan Jash on Dec 27, 2008 3:43 PM
solved through xmlSPY
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Hi,
url provided is correct.
http://<host>:<port>/XISOAPAdapter/MessageServlet?channel=<party>:<service>:<channel>;
Refer this blog for accessing WSDL from :
1) WebDynpro :
/people/riyaz.sayyad/blog/2006/05/07/consuming-xi-web-services-using-web-dynpro-150-part-i
/people/riyaz.sayyad/blog/2006/05/08/consuming-xi-web-services-using-web-dynpro-150-part-ii
2) From Visual Composer :
regards
Ganga
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Hi Ganga,
Thank you so much for your quick reply.
I have checked both blogs. I case of WD, I don't want to access the WSDL file from client system. Instead of that I want to access through WSDL URL but not able. Now I am checking the configuration in Visual admin for VC.
I will let you know the result.
Thanks again
Chandan
Hi ,
1) Download the WSDL file and check if the URL is present in file
2)Other workaround if you create model using the File you can the URL from :
When the model is generated, you can browse through the logical ports,the model classes, and so on.
Under Logical Ports, check the value of the Target Address parameter under the model port name
regards
ganga
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