How to open application in new window.

[Former Member]

Hi Experts,

I have a very typical problem. I am using webdynpro java - Adaptive RFC model.From the model, I get the output of a pdf form. Everything goes fine, and clicking on the link of the web dynpro view I am able to open in in a new window.

Now the actual requirement is to launch the pdf window in the first click itself.ie, web dynpro view should not be made visible. i removed the view, and called the code in init() id component controller. But since a 'window component' is always required to launch a web dynpro application, still I get a blank screen(nothing inside it) and a new window as well for pdf. The new window for pdf is because I am using window.open().

IWDWebResource webResource = WDWebResource.getWebResource(wdContext.currentForm_OutputElement().getPdf(), WebResourceType.PDF);
			   String url = null;
			   try {
				   url = webResource.getURL();
				   wdContext.currentContextElement().setMypdfurl(url);
			   } catch (WDURLException e) {
				   wdComponentAPI.getMessageManager().reportSuccess("error in form fetching");
			   }
			   IWDWindow window = wdThis.wdGetAPI().getComponent().getWindowManager().createExternalWindow(url, "ConfirmationForm", false);
			wdComponentAPI.getMessageManager().reportSuccess("url " + url);
						   window.open(); 

.

Is there any way in which I can set this url in the launch application window of web dynpro application. Else can I get away with the launch window in some way...I want just one window to open having the pdf inside it.This pdf is coming from backend.

Please help.

Thanks,

Sonali.

[Former Member]

Solved by using InteractiveFormUIElement in the mode:UsePdf.