File name from file path

[Former Member]

Hi Friends,

i am using METHOD CL_GUI_FRONTEND_SERVICES=>FILE_OPEN_DIALOG

i want to know the file name selected from the path.

example : c:\folder\file.txt.

here i want to know which file i have selected. if it is a small path then we can use SPLIT command but if the path selected is long with special chareters then?

urget requirement.

regards

Kumar M.

[Former Member]

You can try FM's:

SO_SPLIT_FILE_AND_PATH

/SAPDMC/LSM_PATH_FILE_SPLIT

DSVAS_DOC_FILENAME_SPLIT

[Former Member]

Hi,

Use the FM: CH_SPLIT_FILENAME to split the file path...

Regards

Shiva

[Former Member]

u can use this function...

CALL FUNCTION 'WS_FILENAME_GET'

EXPORTING

DEF_PATH = 'C:\'

MASK = '*.xls'

MODE = 'O'

TITLE = SY-TITLE

IMPORTING

FILENAME = FILENAME

EXCEPTIONS

INV_WINSYS = 1

NO_BATCH = 2

SELECTION_CANCEL = 3

SELECTION_ERROR = 4

OTHERS = 5.

have a nice day...