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Unable to create Entries in the Z Table -- Make entry in the form 9,999.999

Former Member
0 Kudos

I have created/Copied a standard table to a z Table with 5 fields.

One of the Field should be capbale to hold AAAAA.DDDDDDDDDDDDDD. (ie 5 Place before point and 14 decimal places).

So I have created Domain DEC with 14 decimal places and 19 No Characters.

When I tried creating an Table Entry(REcord), System rejects the value present in this field wth the following

message "Entry 12345.000000 is to long. (Make entry in the form 9,999.99999 or /9,999.99999.)".

One more thing: I have maintained the DEcimal Notation as 1,234,567.89 in the User Defaults(TCode SU01).

Please help !

RJ

1 ACCEPTED SOLUTION

Former Member
0 Kudos

Hi,

So as you said the notaion comma is also included in the count of places.

so try giving as1,234.00000 - shouldn't give error.

if no error then increas the total no. of character in domain to 20 and check giving value 12,345.000000...

Regards

Salini.

1 REPLY 1

Former Member
0 Kudos

Hi,

So as you said the notaion comma is also included in the count of places.

so try giving as1,234.00000 - shouldn't give error.

if no error then increas the total no. of character in domain to 20 and check giving value 12,345.000000...

Regards

Salini.