replace charachters

[Former Member]

I have abcc345. i need to replace all the charachters by spaces.

incase i have asdfghj00001 again all charachters by spaces.

but number remains the same.

in all cases i just need to replace the charachters numbere remaining the same

[Former Member]

Hi use the keywords REPLACE and CONDENSE.

cheers!!

[former_member329859]

hi,

str = abcc3345.

str1 = str+4(1).

str2 = str+4(4) = 3345. then take it in anather variable

same for below one with some modification

[Former Member]

Hi,

Use this....

DATA : lv_field type char20 value 'asdfghj00001',
       moff type i,
       lv_strlen type i,
       lv_length type i.


find first occurrence of regex '\d' in lv_field match offset moff.

lv_strlen = strlen( lv_field ).

lv_length = lv_strlen - moff.

write : / lv_field+moff(lv_length).

Hope it will helps

[Former Member]

HI,

See if one variable has value like abc456.

simply declare one variable with type N.

example ..

data:  
  w_var1(20) type c value 'ABC1101',
  w_var2(20) type N.

w_var2 = w_var1.

write : / w_var2. 
Then simply it writes ....  1101.

hope u got it..

this is the concept of type conversion...................

Regards

Sunil Kumar Mutyala.

[Former Member]

Hi,

Use Replace as follows;

DATA lv_text TYPE string VALUE 'ab000cdeSDFf34534gh1ASDF234ijk5abc0'.
WRITE : /,'Before Replace :',lv_text.
REPLACE ALL OCCURRENCES OF REGEX '[A-Za-z]' IN lv_text WITH ''.
WRITE : /,'After Replace :',lv_text.

Output:

Before Replace : ab000cdeSDFf34534gh1ASDF234ijk5abc0

After Replace : 00034534123450

Remember that there is no space between the single quotes in the WITH clause of the REPLACE statement.

Regards

KArthik D

[Former Member]

Hi,

You can also use;

REPLACE ALL OCCURRENCES OF REGEX '[[:alpha:]]' IN lv_text WITH ''.

Regards

Karthik D