step by step process to add a inputfield as a column in the table

[Former Member]

Hi,

Could somone give me the steo by step process for adding the inputfield as a column to the table.

regards

swathi

[Former Member · Accepted solution]

Hi,

1. Right click on the Table UI element (in the Outline view) and from the context menu choose Insert -> TableColumn. This will create a TableColumn entry under the Table UI element.

2. Right click on the newly created TableColumn and from the context menu select "Insert TableCellEditor". This will pop-up a window with all the available UI elements. Select InputField from this window.

3. Bind the "value" property of this InputField to the appropriate context attribute.

Regards,

Satyajit.

[Former Member · Accepted solution]

Hi,

I have already done the steps you have specified.Iam stuck with the cardianlity that a context attribute need to have when binding.

regards

swathi

[Former Member · Accepted solution]

Resolved on my own

[Former Member]

Hi,

follow the below pdf ,it will explain step by step to create the table.

Developing with Tables in Web Dynpro Java

https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/90ac0015-d1c5-2a10-d788-aed89990...

Regards,

ramesh

[amolgupta]

easiest way to create a table....

right click on the view->templates->table....

from there you can pick it up on your own.

regards,

-Amol

[Former Member]

1. Select the Table Column In which you would like to create Input Field.

2. Expand the Table Column and Delete the Text View-Editor that is created by default as a Table cell.

3. Once you deleted the Text view , now right click the Table column and from the context menu insert TableCellEditor

4. There you will see different types like Radio Button, Input Field, etc...... and select Input Field

Repeat above steps wherever you need.

Thanks

Krishna