PL_TIMEOUT Error

[Former Member]

Hi All

I am getting the following error when i am using the wait step in the BPM process.

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>

- <!-- Call Adapter

-->

- <SAP:Error xmlns:SAP="http://sap.com/xi/XI/Message/30" xmlns:SOAP="http://schemas.xmlsoap.org/soap/envelope/" SOAP:mustUnderstand="1">

<SAP:Category>XIServer</SAP:Category>

<SAP:Code area="INTERNAL">PL_TIMEOUT</SAP:Code>

<SAP:P1 />

<SAP:P2 />

<SAP:P3 />

<SAP:P4 />

<SAP:AdditionalText />

<SAP:ApplicationFaultMessage namespace="" />

<SAP:Stack>Timeout condition of pipeline reached</SAP:Stack>

<SAP:Retry>N</SAP:Retry>

</SAP:Error>

when i removed the wait step from the BPM it is giving no error.

can any one of you please provide the input on the same.

Thanks

Rinku Gangwani

[aashish_sinha]

Hi,

Use the following steps in BPM

1) Receive Step (Opens S/A Bridge)

Properties:

Name: Receive1

Message: Request_var

Start Process: yes

Mode: Opens S/A Bridge

Sync Inf: Sync_AI (Abstract Sync interface)

Sync_AI:

Output msg is Request_MT

Input msg is Response_MT

Request_var is interface variable referring to Request_msg_AI an abstract async

Request_msg_AI:

msg type is Request_MT

2) Send Step (synchronous)

Properties:

Name: Send1

Mode: Synchronous

Synchronous interface: Sync_AI

Request Message: Request_var

Response Message: Response_var

Receiver from: Send Context

Sync_AI:

Output msg is Request_MT

Input msg is Response_MT

Response_var is interface variable referring to Response_msg_AI an abstract async inf.

Response_msg_AI:

msg type is Response_MT

3) Send Step (Closes Bridge)

Properties:

Name: Send2

Mode: Closes S/A Bridge

Message: Response_var

Opened by:Receive1

Hope this will clarify you.

Regards

Aashish Sinha

[Former Member]

Hi Rinku

I think u r using outbound proxy with synchronous mode. please check the sender proxy system admin setting. i.e the setting for a synchronous proxy timeout parameter....in sender R/3 system.

Regards

Raj

Edited by: raj sharma on Aug 27, 2008 9:20 AM

[Former Member]

Hi,

Refer Below threads, Your problem might be solved

"Award points if it is helpful"

Regards,

Jayasimha Jangam

[Former Member]

Hi,

Probably you have to code in the serivce to wait for particualr second,because sending application has to wait for that long...probably you can use wait after opening the socket in ur service code

Check this blog..

Regards,

Yuga