on 08-12-2008 6:49 PM
Hi,
I'm facing an issue when trying to get all querystring parameters in a WD JAVA app:
1. URL = http://sap.com?ab=1&ab=2&ba=3
Note that key "ab" appears twice.
2. I'm using following code to get the parameters:
String queryStringParams = "";
Map parameters = WDWebContextAdapter.getWebContextAdapter().getRequestParameterMap();
for (Iterator paras = parameters.keySet().iterator(); paras.hasNext();)
{
String key = (String) paras.next();
String value = WDWebContextAdapter.getWebContextAdapter().getRequestParameter(key);
queryStringParams = queryStringParams + "&" + key + "=" + value;
}
3. As result, queryStringParams = "ab=1&ba=3"
How can I get both "ab" values?
Thanks,
Valmir Führ
Hi All,
I've found a solution:
String queryStringParams = "";
IWDRequest request = WDProtocolAdapter.getProtocolAdapter().getRequestObject();
Enumeration paramNames = request.getParameterNames();
while (paramNames.hasMoreElements())
{
String name = (String) paramNames.nextElement();
String[] parameterValues = request.getParameterValues(name);
for (int j = (parameterValues.length-1); j >= 0; j--)
{
String value = parameterValues[j];
queryStringParams = "&" + name + "=" + value + queryStringParams;
}
}
This code will build queryStringParams in the same order the params were sent.
Regards,
Valmir Führ
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